- 5 Fold Serial Dilution
- Serial Dilution Conclusion
- Two Fold Serial Dilution Method
- Three Fold Serial Dilution
1 Answer
Jun 18, 2014
Answer:
You multiply the original concentration by the dilution factors for each dilution.
A dilution is a reduction in the concentration of a solution. A serial dilution is a series of repeated dilutions that provides a geometric dilution of the original solution. This is commonly performed in experiments that involve concentration curves on a logarithmic scale. Serial dilutions are used extensively in biochemistry and microbiology. A three-fold dilution would be a tripling of the solution volume, as in going from 1 to 3. Although not a serial dilution, the below is an example of a two-fold dilution. Problem #4: To make a two-fold dilution of 10 mL of solution, what amount of solvent would you use and how would you do this?
Explanation:
A serial dilution is any dilution in which the concentration decreases by the same factor in each successive step.
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![3 Fold Serial Dilution 3 Fold Serial Dilution](/uploads/1/2/4/8/124822785/928206642.png)
In serial dilutions, you multiply the dilution factors for each step. Mavis beacon windows 10 latest version.
The dilution factor or the dilution is the initial volume divided by the final volume.
For example, if you add a 1 mL sample to 9 mL of diluent to get 10 mL of solution,
Example 1
What is the dilution factor if you add 0.2 mL of a stock solution to 3.8 mL of diluent?
Example 2
If you did the above dilution four times, what would be the final dilution factor?
Solution 2
Remember that serial dilutions are always made by taking a set quantity of the initial dilution and adding it successively to tubes with the same volume. So you multiply each successive dilution by the dilution factor.
You would transfer 0.2 mL from Tube 1 to 3.8 mL of diluent in Tube 2 and mix. Hackers movie wiki. Then transfer 0.2 mL from Tube 2 to 3.8 mL of diluent in Tube 3 and mix. Repeat the process until you have four tubes.
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The dilution factor after four dilutions is
5 Fold Serial Dilution
If the concentration of the original stock solution was 100 µg/µL, the concentration in Tube 4 would be
Serial Dilution Conclusion
100 µg/µL × #1/160000# = 6.25 × 10⁻⁴ µg/µL
Two Fold Serial Dilution Method
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